The cutoff wavelength for a photon able to create electron hole pair in a semiconductor having energy band gap of 1.6eV is :
(a) 7275 Å
(b) 8050 Å
(c) 7000 Å
(d) 7758 Å
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Answer:
approx d will be the answer
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Explanation
There is a wavelength and a frequency for every photon. The distance between two electric field peaks with the same vector is known as the wavelength. The number of wavelengths a photon travels across each second is what is known as its frequency. A photon cannot truly have a color, unlike an electromagnetic wave.
Now we know
E = H*C/λ
Therefore
1.6*1.6*10^-19 = 6.6*10-34*10^8 / λ
Therefore
λ= 6.6*10^-34*10^8/1.6*1.6*^10-19
Therefore λ = 7.7*10^-7
Hence the wavelength is 7758 Â
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