Question

The cyclic integral of (δQ−δW) for a process is positive negative zero or unpredictable

Answer 1

as per first law of thermodynamics we know that

$\delta Q = \Delta U + \delta W$

now for a cyclic process if we apply the first law

we know that for all cyclic process initial and final state is always same

also we know that change in internal energy is a state function and depends only on initial and final state

so here for all cyclic integral we can say

$\Delta U = 0$

so we have

$\deltaQ = \deltaW$

$\delta Q - \delta W = 0$

so it must be zero for all cyclic integrals

Answer 2

Answer:

only for cyclic process it iz zero but for for a process it is unpredictable, it may be +ve -ve or 0