Question

The cylinderical cans have equal base area.If one of the can is 15cm high and other is 20cm high find the ratio of the Volume.​

Answer 1

Answer:

3:4

Step-by-step explanation:

Given

• Height of first cylinder = 15

• Height of second cylinder = 20

To find

• Ratio of there area

$\sf \boxed{ \sf \: volume \: of \: cylinder = \pi {r}^{2} h}$

$\sf \: volume \: of \: first \: cylinder = \pi {r}^{2} 15$

$\sf volume \: of \: second \: cylinder = \pi {r}^{2} 20$

As we know that area and base are same , we need not do any kinda further calculations by plugging extra number.

Now , arranging the obtained value in ratio form :

$\implies \huge \frac{ {\cancel{\pi {{r}^{2}}}}15 }{ \cancel{\pi {r}^{2} }20}$

$\sf \implies \: \frac{15}{20} = \frac{3}{4}$

Ratio = 3:4

What you need to know ?

• Volume : 3-dimensional space enclosed by a boundary or occupied by an object.

• Ratio is comparison between two known sets of values.

Answer 2

$\sf Volume \: of \: cone = πr²h$

$\sf Ratio \: of \: volumes = \frac{\pi {r}^{2}h_{1} }{\pi {r}^{2} h_{2}}$

$\sf h_1 = 15cm$

$\sf h_2 = 20cm$

$\sf Ratio \: of \: volumes = \frac{\pi {r}^{2} \times 15 }{\pi {r}^{2} \times 20}$

$\sf Ratio \: of \: volumes = \frac{15 }{20}$

$\sf Ratio \: of \: volumes = \frac{3}{4}$

$\sf {\red{Ratio \: of \: volumes \: = 3 \colon 4}}$