Math, asked by dearsonpou44, 1 year ago

The cylindrical pipe of length 28m and diameter 5cm. Find the total radiating surface in the system.

Answers

Answered by aqibjawedkhan9p5p8sa

Answer:Mark it as brainliest please

Attachments:

aqibjawedkhan9p5p8sa: Mark it as brainliest

dearsonpou44: =2×22/7×0.05/2×28

=22×0.05×4

=4.4m sq

What about the radius?

aqibjawedkhan9p5p8sa: No need of it

dearsonpou44: But the question itself said about 28 m and 5 cm? Isn't there any difference between meter and cm?

aqibjawedkhan9p5p8sa: thats why we change meter into centimeter

dearsonpou44: ok great thanks

aqibjawedkhan9p5p8sa: Thanks

Answered by GlamorousGirl

$\huge\mathbb\pink{Hey \: Mate!!}$

${\huge{\red{\underline{\overline{\mathit{\red{ANSWER↓}}}}}}}$

h = 28m

2r=5cm

$\therefore$ r = $\large\dfrac{5}{2}$ cm = $\large\dfrac{5}{2×100}$

= $\large\dfrac{5}{200}$ m = $\large\dfrac{1}{40}$ m

$\therefore$ Total radiating surface in the system

= ${\small{\boxed{\sf{\pink{2πrh}}}}}$

= 2 × $\large\dfrac{27}{7}$ × $\large\dfrac{1}{40}$ × 28 = ${\underline{\underline{4.4m²}}}$

The area of the radiating surface of system is 4.4 m²

$\\ \\ \\$

$\large\underline\mathbb\red{HOPE \: THIS \: HELPS \: U}$

$\large\fbox\colorbox{pink}{Mark \: as Brainliest}$

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