Question

The cylindrical tube of a spray pump has radius R.
One end of it has n fine holes, each of radius r. If
the speed of liquid in the tube is v. the speed of
the ejection of the liquid through the holes is​

Answer 1

Answer:

v =VR^2/Пr^2

Explanation:

Using equation of continuity, Av=constant

A  

1

​  

v  

1

​  

=A  

2

​  

v  

2

​  

 

∴πR  

2

V=(nπr  

2

)v  

′

 where nπr  

2

 is the total area of n fine holes.

⇒v  

′

=  

nr  

2

 

VR  

2

 

​