Question

the cylindrical tube of spray pump has radius R one end of which has n fine holes each of radius r the if the speed of the liquid in the tube is V the speed of the injection of the tube through the holes is

Answer 1

hence, speed of injection of the tube through the holes is as follows....

Answer 2

Answer:

Area of cross-section of the spray pump, A1 = 8 cm2 = 8 × 10–4 m2

Number of holes, n = 40

Diameter of each hole, d = 1 mm = 1 × 10–3 m

Radius of each hole, r = d/2 = 0.5 × 10–3 m

Area of cross-section of each hole, a = πr2 = π (0.5 × 10–3)2 m2

Total area of 40 holes, A2 = n × a

= 40 × π (0.5 × 10–3)2 m2

= 31.41 × 10–6 m2

Speed of flow of liquid inside the tube, V1 = 1.5 m/min = 0.025 m/s

Speed of ejection of liquid through the holes = V2

According to the law of continuity, we have:

A1V1 = A2V2

V2 = A1V1 / A2

= 8 × 10-4 × 0.025 / (31.61 × 10–6)

= 0.633 m/s

Therefore, the speed of ejection of the liquid through the holes is 0.633 m/s.