Question

the cylindrical tude open at both ends is made of metal .the internal diameter of the tude is 10.4 cm and its lenght is 25 cm the tickness of the metal is 8mm everywhere calculate the volume of the metal

Answer 1

given internal diameter of cylindrical tube =10.4cm
so,internal radius =5.2 cm
length of tube =25cm
now
now
volume of cylindrical tube=pi. {R^2-r^2} h
where R is external radius
I.e. R=5.2 +0.8 =6cm
r=5.2 cm
now volume =22/7 x {(6^2-(5.2)^2} x 25cm^3
= 703.36 cm^3