Math, asked by Messi10000, 1 year ago

the cylindrical vessel open at the top has a radius 10 cm and height 14 cm find the total surface area of the vessel take 5 is equal to 3.14


JunaidMirza: Why should I take 5 = 3.14?
Messi10000: No sooru its pi
Messi10000: Sorry

Answers

Answered by JunaidMirza
600
Area = 2πrh + πr²

A = 2*3.14*10*14 + 3.14*10^2

A = 1193.2 cm²
Answered by mindfulmaisel
275

Answer:

The total ‘surface area of the vessel’ is \bold{1193.2\ \mathrm{cm}^{2}}.

Solution:

Area of the cylinder includes lower curved surface, upper curved surface, lateral surface including height.

Given that the cylinder is open at the top. This means that the surface area of the lid should not be considered.

So, only lateral surface and lower surface should be considered.

Area of the cylindrical surface =2 \pi r h+\pi r^{2}

Where r is the radius of the curved surface, h is the height between two curved surfaces as shown in the below attached figure.

Area =2 \pi r h+\pi r^{2}=2 \times 3.14 \times 10 \times 14+3.14 \times 10 \times 10\left(\pi \text { is } 3.14_{,}\ r=10, h=14\right)

=879.2+314\\ \\=1193.2\ \mathrm{cm}^{2}

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