Question

The d orbitals which are involved in hybridisation of central atom of icl4-

Answer 1

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Answer 2

Tetrachloride iodide Ion:

$I {Cl_4}^{ - }$

Iodine = 7 valence electron

Chlorine = 7 valence electron.

• Total valence electrons in Tetrachloride iodide Ion:

$I {Cl_4}^{ - } = 7 + 4(7) = 36$

It means number of Iodine molecule is 1 and Chlorine molecule is 4 and both molecule has same valency .

• The hybridization is :

$I {Cl_4}^{ - } =sp³d²$

It has four bond pairs and lone pairs . It has octahedral geometry.

• Shape of the Ion - square planar structure.

Hence,

The d-orbitals which are involved in hybridisation of central atom of Tetrachloride iodide Ion is Sp³d².

Project code #SPJ3