Question

the daigonal of rhombous is 16 cm and 30 cm find its perimeter​

Answer 1

Answer:

perimeter of rhombus = 1/2 x d1 x d2

1/2 x 16 x 30

ans = 240 cm

Answer 2

Question

the daigonal of rhombous is 16 cm and 30 cm find its perimeter.

Answer

we can write it as8 cm +8 cm = 16 cm and 15 cm + 15 cm = 30 cm

Since diagonal of a rhombus bisects each other

By using the formula of pythagoras.

$\large\boxed{\bf{(h) ^{2} = {(p)}^{2} + {(b)}^{2} }}$

Put values in the formula.

$\implies\bf{( h )^{2} = ( 8 )^{2} + ( 15 )^{2}}$

$\implies\bf{( h )= ( 64 ) + ( 225 )}$

$\implies\bf{h²= 289}$

By taking square root on both sides.

$\implies \bf{{\sqrt{h}^{2}}}= {\sqrt{289}}$

$\implies\bf{h=17}$

Perimeter of the rhombus = 4 × side

= 4 × 17

= 68cm Ans

Therefore the perimeter of thrombus is 68cm.