The daily cost of milk (in Rs.) supplied to 25 houses in a locality are given below: Cost(in Rs.) Number of houses 40-50 50-60 60-70 70-80 80-90 90-100 6 If one house is chosen at random, find the probability that: (i) the milk bill of the house lies between Rs. 60 and Rs. 80. (ii) house is paying at the most Rs. 69. for the milk bill.
Answers
Answer:
8/25,12/25
Step-by-step explanation:
number of favourable cases= (60,70) and (70,80) as milk bill lies between 60 and 80. Hence number of favourable houses
= 3 + 5 .
= 8.
total number of cases= total number of houses= 25.
P(bill is between 60 and 80) = number of favourable cases/ total cases=8/25
ii) number of favourable cases= (40,50) , (50,60) , (60,70) .
= 4 + 5 +3
= 12.
(60,70) is also included because range (60,70) is actually (60,69)
this follows for all ranges for example (40,50) is actually range (40,49) because 50 is included in (50,60).
total number of cases=25.
P(houses paying at most 69 Rs for bill)= 12/25
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Step-by-step explanation:
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