The daily cost of milk (in Rs) supplied to 25 houses in a locality are given below
:
If one house is chosen at random, find the probability that ;
(a) the milk bill of the house lies between Rs 60 and Rs 80
(b) house is paying at the most Rs 69, for the milk bill
(c) the milk bill of the house is below Rs 50
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a) Total number of houses paying the milk bill between \(Rs. \ 60\) and \(Rs. \ 80\)\(=3+5=8\).
b) 3 + 5 . = 8. total number of cases= total number of houses= 25.
c) The number of houses paying the bill for milk below \(Rs. 50=4\).
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Step-by-step explanation:
Total number of houses = 25
(a) Total number of houses paying milk bill between 60 and 80 = 3 + 5 = 8
.. P (milk bill between 60 and 80) = 8
25
(b) Total number of houses paying milk bill at the most 69 =
.. P (milk bill at the most 69) = 12
25
(c) Total number of houses paying milk bill below 50 = 4
.. P (milk bill below 50) 4 =
25
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