Question

The data regarding marks obtained by 48 students of a class in a class test is given below. Calculate the modal marks of

students. [2]

Marks obtained 0-5 5- 10 10-15 15-20 20-25 25-30 30-35 35-40 40-45 45-50

Number of students 1 0 2 0 0 10 25 7 2 1​

Answer 1

step by step explanation:

hope it helps u :)

Answer 2

Answer:

30.27

Given:-

marks obtain. number of student

0-5 1

5-10 0

10-15 2

15-20 0

20-25 0

25 -30 10

30-35 25

35-40 7

40-45 2

45-50 1

here,

mode or modal :-

• the mode is the value of the varibale ,whichcharacterizes more items than any other value
• it is the valye of greatest freqency or more precisely greatest frequency density
• Graphically it is the value of the X - axis below the peak of the frequency curve

hence,

fisrt we will solve the mode value

as all we know formula of mode or modal

$mode \: = l_{1} + \frac{f_{1} - f_{0}}{( \:f_{1} - f_{0}) + (f_{1} - f_{2})} \times( l_{2} - l_{1})$

here the maximum frequency is 25

corresponding to the class interval 30- 35

therefor:-

the modal class is 30 - 35

$l_{1} = 30 \\ l_{2} = 35 \\ f_{1} = </strong><strong>2</strong><strong>5</strong><strong> \\ f_{2} = </strong><strong>7</strong><strong> </strong></p><p><strong>\\ f_{0} = </strong><strong>1</strong><strong>0</strong><strong>$

$mode \: = l_{1} + \frac{f_{1} - f_{0}}{( \:f_{1} - f_{0}) + (f_{1} - f_{2})} \times( l_{2} - l_{1}) \\ \\ mode \: = 30 + \frac{25 - </strong><strong>1</strong><strong>0</strong><strong>}{(25 - </strong><strong>1</strong><strong>0</strong><strong>) + (25 -</strong><strong>7</strong><strong>} \times (35 - 30) \\ \\ mode = 30 + \frac{1</strong><strong>5</strong><strong>}{</strong><strong>1</strong><strong>5</strong><strong> + 1</strong><strong>8</strong><strong>} \times 5 \\ \\ mode = 30 + \frac{1</strong><strong>5</strong><strong>}{33} \times 5 \\ \\ mode = 30 + \frac{</strong><strong>2</strong><strong>5</strong><strong>}{11} \\ \\ mode = 32.</strong><strong>2</strong><strong>7</strong><strong> \: aprox.$