Math, asked by 786687harinder24, 1 month ago

The daughter's age 40 year less than her mother. After ten year mother'age twice time greater than her daughter'age. What is the present age of mother?​

Answers

Answered by johnwick97
0

Answer:

Refer to the attachment

Attachments:
Answered by nidhimenon91
0

Answer:

Let age of daughter =C

Let age of her mother =M

Then, M−10=4(C−10) or M=4C−30

and, M+10=2(C+10) or M=2C+10

Thus, 4C−30=2C+10

2C=40

C=20 years

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