Math, asked by 786687harinder24, 20 hours ago

The daughter's age 40 year less than her mother. After ten year mother'age twice time greater than her daughter'age. What is the present age of mother?​

Answers

Answered by johnwick97
0

Answer:

Refer to the attachment

Attachments:
Answered by nidhimenon91
0

Answer:

Let age of daughter =C

Let age of her mother =M

Then, M−10=4(C−10) or M=4C−30

and, M+10=2(C+10) or M=2C+10

Thus, 4C−30=2C+10

2C=40

C=20 years

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