Question

the de brogli wavelength of H atom is 3 .329a​

Answer 1

Answer:

not h atom

it should be he+ ion

cuz he+ion have wavelength of 3.329 Å

MATE IF YOUR QUESTION IS THIS THEN ANSWER IS BELOW

The de Broglie's wavelength of electron of He+ ion is 3.329Å. If photon emitted upon de-excitation of this He+ ion is made to hit H atom in its ground state so as to liberate electron from it, what will be the de Broglie's wavelength of photoelectron?

ANSWER : E= hc/L...L=3.329 A

By putting the corresponding values we get E=5.947?10^-16 J

Now de broglie wavelength= h/root(2mE)

By puttong h=6.6?10^-34,m=9.1x10^-31

E=5.947?10^-16

We get L~2.351 A