the de broglie wave length of a particle moving with the potential difference 100 volt
Answers
Answer:
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❥︎A᭄ɴsᴡᴇʀ࿐:−
Given :
Mass of bullet , m = 50 gm = 0.05 m .
Initial velocity of bullet , u = 600 m/s .
Velocity of bullet after penetrating , v = 150 m/s .
To Find :
Energy of bullet used to penetrate the target .
Solution :
We know , by conservation of energy .
Energy used = Loss in kinetic energy
\begin{gathered}\begin{gathered}Energy \ used = K.E_i-K.E_f\\\\Energy \ used = \dfrac{1}{2}mu^2-\dfrac{1}{2}mv^2\\\\Energy \ used =\dfrac{m}{2}(u^2-v^2)\\\\Energy \ used =\dfrac{0.05}{2}\times (600^2-150^2)\\\\Energy \ used =8437.5\ J\end{gathered}\end{gathered}
Energy used=K.E
i
−K.E
f
Energy used=
2
1
mu
2
−
2
1
mv
2
Energy used=
2
m
(u
2
−v
2
)
Energy used=
2
0.05
×(600
2
−150
2
)
Energy used=8437.5 J
Learn More :
Conservation of energy
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