Question

The de Broglie wave length of a particle of mass 1 mg moving with a velocity 1 m/s will be(a) 10⁶ h m(b) 10⁻² h m(c) 10⁴ h m(d) 10² h m

Answer 1

lambda=h/p

p=mv

mass should be put in kg.

1mg=10^-6 kg.

& v=1m/s

lambda=h/10^-6×1

lambda=10^6 h m..answer

Answer 2

The correct answer is 10⁶ hm. (option a)

Given,

Mass of the particle = 1mg = $10^{-6}$ kg

Velocity of the particle = 1 m/s

To Find,

the de Broglie wavelength of the particle.

Solution,

λ = $\frac{h}{mv}$ = $\frac{h}{10^{-6} X 1 }$ = $10^{6}$ hm

∴Hence, the de Broglie wavelength of the particle is 10⁶ hm.