Question

The de-broglie wavelength associated with a ball of mass 1 kg having K.E 0.5 joule is _____

Answer 1

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ur answer to the question. ......^_&^^

Answer 2

Answer: The de-Broglie wavelength is $6.6\times 10^{-34}m$

Explanation:

De-Broglie wavelength is calculated by using the formula:

$\lambda=\frac{h}{mv}$      .....(1)

where,

$\lambda$ = wavelength of electron

h = Planck's constant = $6.6\times 10^{-34}Js$

m = mass = 1 kg

v = velocity of electron (to be calculated from kinetic energy)

Formula used to calculate kinetic energy of an electron is given as:

$E=\frac{1}{2}mv^2$

$E=\frac{1}{2}mv^2$

Putting values of energy and mass in above formula, we get:

$0.5J=\frac{1}{2}\times 1kg\times v^2\\\\v=1m/s$

Now, putting all the values in equation 1, we get:

$\lambda=\frac{6.6\times 10^{-34}kgm^2s^2/s}{1kg\times 1m/s}\\\\\lambda =6.6\times 10^{-34}m$

Hence, the de-Broglie wavelength is $6.6\times 10^{-34}m$