Question

the de Broglie wavelength associated with a ball of mass 120gram moving at a speed of 20 metre per second
3.5×10^-34
2.8×10-^34
1.2
2.1
please answer it ...it's urgent​

Answer 1

Answer:

2.8×10^-34

Explanation:

de Broglie wavelength lemda = h÷mv

after inputting their values the answer will come

Answer 2

Given:

Mass of the ball = 120 gm = $\frac{120}{1000} \:kg$ = 0.12 kg

Velocity of the ball = 20 m/s

To find:

The De Broglie wavelength of the given ball

Solution:

We know that,

The De Broglie's wavelength of a moving particle is given by,

$\boxed{\bold{\lambda = \frac{h}{\rho}= \frac{h}{m\:v}}}$

where

λ = De Broglie's wavelength in meters

ρ = momentum of the particle in kgm/s

m = mass of the particle in kg

v = velocity of the particle in m/s

h = Planck's constant = 6.62 × 10⁻³⁴ Js

Now, we will substitute the value of m & v of the given ball and h in the above formula to find the value of λ.

$\lambda = \frac{6.62\times10^-^3^4}{0.12\:\times\:20}$

⇒ $\lambda = \frac{6.62\times10^-^3^4}{2.4}$

⇒ $\lambda =2.758\times10^-^3^4$

⇒ $\bold{\lambda}$ ≈ $\bold{2.8\times10^-^3^4}$ $Js$ ← option (2)

Thus, the De Broglie's wavelength associated with the ball of mass 120 g moving at a speed of 20 m/s is $\underline{\bold{2.8\times10^-^3^4}\:Js}$.

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