The de Broglie wavelength associated with a ball of mass
200 g and moving at a speed of 5 m/h, is of the order of
(h = 6.625 × 10⁻³⁴ Js)
(a) 10⁻¹⁵ m (b) 10⁻²⁰ m (c) 10⁻²⁵ m (d) 10⁻³⁰m
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answer : option (d) 10^-30 m
mass of ball, m = 200g = 0.2 Kg
speed of ball, v = 5 m/h = 5/3600 m/s = 1/720 m/s
now linear momentum of ball, P = mv
= 0.2 kg × 1/720 m/s
= 1/3600 Kgm/s
now using De - Broglie's wavelength equation,
λ = h/P
= (6.625 × 10^-34)/(1/3600)
= 6.625 × 10^-34 × 3600
= 2.3850 × 10^-30
so, order of wavelength associated with the ball is 10^-30 and hence option (d) is correct choice.
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