Question

The de Broglie wavelength associated with an electron accelerated
through a potential difference of 100 V is :​

Answer 1

please refer to the image attached

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Answer 2

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• Acceleration potential ${V=100 v}$ .The de Broglie wavelength $\lambda{is}$
• $\lambda{h/p}$=$\frac{1.227}{\sqrt{V}}$ nm
• $\lambda$=$\frac{1.227}{\sqrt{100}}$ nm=${0.124nm}$.
• The de Broglie wavelength associated with an electron in this case is of the order of X-ray wavelengths.