Physics, asked by miranda00, 5 months ago

The de Broglie wavelength of a neutron at 927 °C is lemda. What
will be its wavelength at 27 °C?

Answers

Answered by Braɪnlyємρєяσя

0

Explanation:

The de - Broglie wavelength of a neutron at 27∘C is λ. What will be its wavelength at 927∘C? ⇒λλ2=√(273+927)(273+27)=√1200300=2⇒λ2=λ2.

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