Question

The de broglie wavelength of a neutron at 927 c is lambda what will be it's wavelength in thermal equilibrium with heavy water

Answer 1

2. $wavelength = h \div (2mkt)$
3. m=1.674929 x 10-27 kg
4. k=1.38064852 × 10-23 m2 kg s-2 K-1
5. t=927+273=1200 k