Physics, asked by deepakbabitasharma4, 7 months ago

the De-broglie wavelength of a neutron at 927°c is 'lambda' .what will be it's wavelength at 27°c?

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Answered by mumtaz306

2

Answer:

The de - Broglie wavelength of a neutron at 27∘C is λ. What will be its wavelength at 927∘C? ⇒λλ2=√(273+927)(273+27)=√1200300=2⇒λ2=λ2.

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