Question

The de-Broglie wavelength of a neutron at 927°C is ????.
What will be its wavelength at 27 °C ?
(a) ????/2
(b) ???? (c) 2 ???? (d) 4 ????

Answer 1

Answer:

The de - Broglie wavelength of a neutron at 27∘C is λ. What will be its wavelength at 927∘C? ⇒λλ2=√(273+927)(273+27)=√1200300=2⇒λ2=λ2.