Physics, asked by ABHI12451, 9 months ago

The de-Broglie wavelength of a neutron at 927°C is ????.
What will be its wavelength at 27 °C ?
(a) ????/2
(b) ???? (c) 2 ???? (d) 4 ????

Answers

Answered by sampakrish123

0

Answer:

The de - Broglie wavelength of a neutron at 27∘C is λ. What will be its wavelength at 927∘C? ⇒λλ2=√(273+927)(273+27)=√1200300=2⇒λ2=λ2.

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