Physics, asked by kaulinsh9702, 1 year ago

The de-Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature T (Kelvin) and mass m, is:-(a) \frac{h}{\sqrt{3mkT}}(b) \frac{2h}{\sqrt{3mkT}}(c) \frac{2h}{\sqrt{mkT}}(d) \frac{h}{\sqrt{mkT}}

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Answered by choudhary21
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Hey correct answer A

The de-Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature T (Kelvin) and mass m, is:-(a) \frac{h}{\sqrt{3mkT}}(b) \frac{2h}{\sqrt{3mkT}}(c) \frac{2h}{\sqrt{mkT}}(d) \frac{h}{\sqrt{mkT}}
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