Question

The de - Broglie wavelength of a particle moving with a velocity 2.25×10^8m/s is equal to the wavelength of photon. The ratio of kinetic energy of the particle to the energy of the photon is_______ (velocity of light is 3×10^8m/s A) 1/8 B) 3/8 C) 5/8 D) 7/8

Answer 1

Answer:

Since the de-Broglie wavelength depends only on the momentum of particle, both electron and photon must have same momentum. Also, kinetic energy expression can be written as,

K=21mv2=21pv

Hence,

EphotonEelectron=vphotonvelectron=3×1081.5×108=21

HOPE IT HELPS!!!