Question

The de broglie wavelength of a particle moving with a velocity 2.25

Answer 1

The question is not complete. The mass of the particle or the nature of it isn't specified.

The energy in the waveform depends on the frequency or wavelength only.

We use the formula for De Broglie's wavelength = lambda = h c / E
= h c / ( m u c) = h / (m u).
... Answer. .

Because: E = Kinetic energy of particle = h v..
E = p c

p = momentum of particle
m = mass of particle
u = speed of particle
p = m u

v = frequency of photon /electron waveform

v = c / wavelength
c = speed of light = 3 ×10^8 m/s

h = Planck's constant = 6.626 × 10^-34 J-s.

Answer 2

HELLO THERE!

The de-Broglie wavelength of a particle is given by the formula:

$\lambda = \frac{h}{mv}$

Where λ is the de-Broglie wavelength, h is Plank's constant (6.626 x 10⁻³⁴ Js), m is the mass of the body and v is the velocity with which the body is moving.

Now, it seems that some data in your question is missing. The mass or the Kinetic energy of the particle should be known to calculate its de-Broglie wavelength.

Anyways, if K.E. is known, then find the mass of the body by the relation,

K.E. = 1/2 mv², and then put the value of mass in the equation, to get the wavelength.

HOPE MY ANSWER IS SATISFACTORY...

Thanks!