Physics, asked by ronakverma2963, 10 months ago

The de-Broglie wavelength of a proton (mass = 1.6 ×
10⁻²⁷ kg) accelerated through a potential difference of 1 kV
is
(a) 600 A (b) 0.9 × 10⁻¹²m
(c) 7 Å (d) 0.9 nm.

Answers

Answered by Anonymous

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Answered by harshitaczone9

Answer:

(b)

Explanation:

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The de-Broglie wavelength of a proton (mass = 1.6 × 10⁻²⁷ kg) accelerated through a potential difference of 1 kV is (a) 600 A (b) 0.9 × 10⁻¹²m (c) 7 Å (d) 0.9 nm.

Answers

The de-Broglie wavelength of a proton (mass = 1.6 ×
10⁻²⁷ kg) accelerated through a potential difference of 1 kV
is
(a) 600 A (b) 0.9 × 10⁻¹²m
(c) 7 Å (d) 0.9 nm.