Question

The de Broglie wavelength of an electron
in an orbit represented
by the orbital diagram is
(A) 10A​

Answer 1

de Broglie wavelength say l

l = h/mv

and mvr=nh/2π

so l = 2πr/n

r value can be found be 0.529×n² A° formula

now you can substitute and find out the answer

Answer 2

Answer:

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Explanation: