Question

The de-broglie wavelength of an electron in the first orbit of bohr's hydrogen is equal to : radius of orbit perimeter of orbit diameter of orbit half the perimeter of orbit

Answer 1

The de-broglie wavelength of an electron in the first orbit of bohr's hydrogen is equal to : radius of orbit perimeter of orbit diameter of orbit half the - 2970635.

Answer 2

Hey dear,

● Answer -
(b) perimeter of orbit

● Explaination -
Let r be radius of 1st Bohr orbit.

For electron moving in Bohr's orbit -
mvr = nh / 2π
h / mv = 2πr
λ = 2πr
λ = perimeter

De-Broglie's wavelength for electron in first orbit is therefore is equal to perimeter of orbit.

Hope this helps you.
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