CBSE BOARD XII, asked by jasonisrael549, 2 months ago

The de-Broglie wavelength of an electron is 600 nm. The velocity of the electron is: a. 1.8 x 103 ms-1 b. 1.2 x 105 ms-1 c. 5.4 x 103 ms-1 d. 1.2 x 103 ms-1 ​

Answers

Answered by DevyaniRathod04
0

Answer:

According to de Broglie wavelength equation-

λ =h/mv(h is planck's constant, m is mass of electron and v is velocity)

600*10^-9 = 6.62*10^-34/(9.1*10^-31*v)

Now u can calculate it...

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