The de-broglie wavelength of neutron in thermal equilibrium with heavy water at a temperature T ( kelvin) and mass m, is : ?
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Answered by
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thermal neutrons are used in nuclear power plant for initiate chain reaction.
So they are accelerated thermally,so called thermal neutrons.
their kinetic energy is given by Maxwell's theory in thermodynamics that is (3÷2)kT.
here k is Boltzmann constant.
de Broglie wavelength is given by h÷[√(2.m.K)] here K is kinetic energy of matter.
so replace K by (3÷2)kT.
It will give u wavelength= h÷[√(3mkT)]
where h is planks constant
k is Boltzmann constant
T is temperature in Kelvin.
So they are accelerated thermally,so called thermal neutrons.
their kinetic energy is given by Maxwell's theory in thermodynamics that is (3÷2)kT.
here k is Boltzmann constant.
de Broglie wavelength is given by h÷[√(2.m.K)] here K is kinetic energy of matter.
so replace K by (3÷2)kT.
It will give u wavelength= h÷[√(3mkT)]
where h is planks constant
k is Boltzmann constant
T is temperature in Kelvin.
Answered by
0
Answer:
1.45 Angstrom
here's the answer and hope this helps you.
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