Physics, asked by vishavjasrotia453, 1 year ago

The debrogle wavelenght of an electron accelerated with an electric field of v volts is

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Answered by maheshkd
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kinetic energy of that accelerated electron is now e.V ( ie K = e.V) .so replace it in the formula of de-Broglie wavelength of matter ie
lemda ( ie wavelength) = h÷√(2mK) where K is kinetic energy of matter of mass m.
where symbols have their usual meaning.
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