the decay constant of C34 with half life 1.53 seconds is
A) 0.00755 min - 1
B) 27.18 min - 1
C) 0.453 min-1
D) 0.453 min - 1
Answers
Answered by
2
Answer:
B
Explanation:
decay constant = 0.693/ half life = 0.693/1.53 seconds
= 0.452 seconds -¹
= 0.452 ×60 min-¹
= 27.18 min -¹
[1min=60seconds ->1second= 1/60 minutes]
Answered by
0
Answer:
27.18 min-1 is your correct answer
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