Question

The decomposition of a certain mass of CaCO3 gave 22.414 dm3 of CO2 gas at STP. The mass of

KOH required to completely neutralize the gas is; (KOH + CO2
→
KHCO3)

A) 56 g B) 28 g C) 42 g D) 20 g ​

Answer 1

Weight of 11.2 dm

3

of CO

2

gas at STP=

2

44

=22 g

KOH+CO

2

⟶KHCO

3

56 g 44 g

KOH required for complete neutralisation of 22gCO

2

=

44

56

×22=28g.

hope this helps your

please follow me and mark me as brainliest

Regards