The decomposition of ammonia is :
2 NH3(g) = N2(g) + 3 H2(g). If Kp, is 1.5 x
10*3 at 400°C, what is the partial pressure of
ammonia at equilibrium when N2, is 0.10 atm and
H2, is 0.15 atm?
(1) 2.2 x 10-7 atm (2) 4.7 x 104 atm
(3) 2.1 x 103 atm (4) 4.4 x 106 atm
Answers
Answered by
1
Answer:
The decomposition of ammonia is :
2 NH3(g) = N2(g) + 3 H2(g).
If Kp, is 1.5 x
10*3 at 400°C, then, the partial pressure of
ammonia at equilibrium when N2, is 0.10 atm and
H2, is 0.15 atm is
(1) 2.2 x 10-7 atm is the Answer
Similar questions