Chemistry, asked by Bajaj83, 11 months ago

The decomposition of ammonia is :
2 NH3(g) = N2(g) + 3 H2(g). If Kp, is 1.5 x
10*3 at 400°C, what is the partial pressure of
ammonia at equilibrium when N2, is 0.10 atm and
H2, is 0.15 atm?
(1) 2.2 x 10-7 atm (2) 4.7 x 104 atm
(3) 2.1 x 103 atm (4) 4.4 x 106 atm​

Answers

Answered by Anirudhbhardwaj01
1

Answer:

The decomposition of ammonia is :

2 NH3(g) = N2(g) + 3 H2(g).

If Kp, is 1.5 x

10*3 at 400°C, then, the partial pressure of

ammonia at equilibrium when N2, is 0.10 atm and

H2, is 0.15 atm is

(1) 2.2 x 10-7 atm is the Answer

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