Question

The decomposition of dimethyl ether leads to the formation of CH₄, H₂ and CO and the reaction rate is given by Rate = k [CH₃OCH₃]³/² The rate of reaction is followed by increase in pressure in a closed l vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e Rate = k [text] P{CH₃OCH₃} ³/²[/text] If the pressure is measured in bar and time in minutes, then What are the units of rate and rate constants?

Answer 1

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Answer 2

Answer:

bar`-1/2 min - 1

Explanation:

Substances formed = CH₄ H₂ and CO

Rate of reaction = k [CH₃OCH₃]³/²

If pressure is measured in bar and time in minutes, then

Unit of rate = bar min - 1

Rate = k (PCH3OCH3)3/2

= k = Rate / (PCH3OCH3)3/2

Therefore, unit of rate constants (k) = bar min-1  / bar3/2

= bar`-1/2 min - 1