Question

the decomposition of N2O4 and NO2 is carried out at 280k in chloroform . when equilibrium has been established , 0.2 mol of N2O4 and 2×10 power3 mol of NO2 are present in 2 litre solution the equlibrium constant for reaction N2O4 GIVES 2 NO2 is​

Answer 1

Answer:

1*10^-5

Explanation:

N2O4 ⇆ 2NO2 is the reaction for the above question so from here we can get that for time t=0 the concentration of N2O4 will be 1 and the concentration of NO2 will be 0.

Again at time t the concentration will be (1-x) and 2x respectively. So, the value of concentration will be (2*10^-3)/2 for N2O4 and 0.2/2 for NO2. So, the value of Kc will be given as [NO2]^2/[N2O4] which will be equal to [(2*10^-3)/2]^2/[0.2/2]. This on solving we will get the Kc as 1*10^-5.

Answer 2

Answer:

1×10power -5

Explanation:

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