Question

The decomposition of NH3 on platinum surface is zero order reaslction .What is the rate of production of N2 and H2 if k=2.5×10-4

Answer 1

k = 2.5 × 10−4mol−1L s−1

Order of reaction = 0

Decomposition reaction of NH3

Here NH3 has 2 mol then N2 and H2 has 1 and 3 moles respectively

Use the formula of rate of reaction

Use this formula we get

Another formula of rate, Rate = k[NH3]x

Given that order of reaction x = 0

Plug the values we get

Plug the value of k we get

Rate of production of N2= k = 2.5 × 10−4mol L-1s−1

Rate of production of H2= 3k = 3 x 2.5 × 10−4mol L-1s−1= 7.5 × 10−4mol L-1s−1

Answer 2

Answer:

Mark me as brainliest and thank me if the answer is useful

Explanation: