Chemistry, asked by golu2012rxl, 11 months ago

The decomposition of phosphine PH3 procceed to the following equation

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Answered by shourya35813

Decomposition of phosphine (PH3) at 120∘C proceeds according to the equation: 4PH3(g)→P4(g)+6H2(g) It is found that this reaction follows the following rate equation: Rate =k[PH3] The half-life of PH3 is 37.9s at 120∘C.

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