Question

The decrease in potential energy of a ball of mass 40 g which falls from a height 50 m is​

Answer 1

$\:\:\:\: \large \underline {\sf{Given\::}}$

• Mass ( m ) = 40g = 0.04 kg

• Height ( h2 - h1 ) = 50 m

$\large \underline{\boxed{\sf{\pink{Formula\:used\::}}}}$

• Decrease in potential energy , ∆U = mg(h2 - h1)

Now , $\:\:\:\: \large \underline {\sf{Solving\::}}$

• ΔU = 0.04 × 9.8 × 50

• ∆U = 19.6 J

$\:\:\:\: \underline {\sf{\red{Decrease\:in\:potential\:energy\:is\:19.6\:J}}}$

Answer 2

Answer:

Given:

• Mass ( m ) = 40g = 0.04 kg

• Height ( h2 - h1 ) = 50 m

Formula

used:

• Decrease in potential energy , ∆U = mg(h2 - h1)

Now ,

Solving:

• ΔU = 0.04 × 9.8 × 50

• ∆U = 19.6 J

Decreaseinpotentialenergyis19.6J.