Question

The decreasing order of boiling points is

(a) n-Pentane > iso-Pentane > neo-Pentane

(b) iso-Pentane > n-Pentane > neo-Pentane

(c) neo-Pentane > iso-Pentane > n-Pentane

(d) n-Pentane > neo-Pentane > iso-Pentane​

Answer 1

Answer:

(c) neo-Pentane > iso-Pentane > n-Pentane

Answer 2

Explanation:

Solution

The correct option is A n-Pentane > iso-Pentane > neo-Pentane

The more the surface area, the higher the Van Der wall's interactions. The higher the interactions, the higher the boiling/melting points will be,

We know that a linear alkane has higher surface area than its branched successors in order.

Hence the order will be:

n-Pentane > iso-Pentane > neo-Pentane