Question

The decreasing order of solubility of silver

halides is (polar solvent)

1) AgBr > AgF > AgI > AgCl

2) AgCl > AgF > AgBr > AgI

3) AgF > AgCl > AgBr > AgI

4) AgI > AgBr > AgCl > AgF​

Answer 1

Answer:

option 3

Explanation:

as AgI is most reactive hence it is least soluble halide in polar solvent

Answer 2

Answer:

ANSWER

The decreasing order of solubility of silver halide is AgF>AgCl>AgBr>AgI

On moving down the group of halogens, the ionic size increases and hydration energy decreases. Hence, the solubility decreases.

Explanation:

Hope it helps you ✌✌✌✌✌✌

mark me as brainliest