The decreasing order of vibrational frequency for C_Cl, C_Br, C_O, and C_H?
a) C_H, C_C, C_O, C_Cl, C_Br
B) C_Cl, C_Br, C_C, C_H, C_O
c) C_O, C_H, C_Br, C_Cl, C_C
d) C_Br, C_Cl, C_C, C_O, C_H
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Answer:
d is the answer my friend
coz the electronegativity of BR is greater than CLgreater than c greater than O greater than h
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0
The correct option is a.
- The vibrational frequency of a bond is inversely proportional to the square root of the masses of atoms.
- The mass of C, H, O, Cl, Br is in the order-
- H<C<O<Cl<Br
- Thus, the vibrational frequency is maximum for C-H as H has the lowest mass and minimum for C-Br as Br has the highest mass.
- Thus the decreasing order of vibrational frequency is-
- C_H> C_C>C_O>C_Cl>C_Br
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