Question

the deensity of 3M solution of NaCl is 1.25 g mL-1. Calculate molality of the solution.

Answer 1

Answer:

2.79m is the molality

Explanation:

refer attachment for explanation!!!

Answer 2

simple question dude

molality=moles of solute/mass of solvent(in lg)

molarity=molesof solute/volume of solution

let the volume,of solution be unit litre

then,in that case

3=moles of solute/volume of solution

moles of solute=3

mass of the solute=3×40 (1mols of NaCl=40g)

=120g=.12kg

since volume is taken as 1unit L,so

mass of liquid=1250g or 1.25kg

mass of solvent=mass of solution-mass of solute

=1.25-.12=1.13kg

now molality=3/1.13

=300/113

=2.65m(mole/kg)