Computer Science, asked by Deepak6464, 10 months ago

The default style applied to cells

Answers

Answered by Nandzzz

4

Explanation:

NORMAL :

The default style is called "Normal" and this is used for both text and numbers and is also used to determine the font used for the row and column headings......

I HOPE IT HELPS U....

PLZZZ MARK ME AS BRAINLIST.......

TQ.....

Answered by geetabejgam

0

Answer:

the default style is normal and thisis used for both text and numbers and is also used to determine the front used for the row and column headings

Previous Question

Next Question

Similar questions

English, 5 months ago

What does McMurdo’s revelations about killing Dunn and Menzy’s murderers and warning Chester Wilcox tell you about his way of looking at these deeds and about his personality?

Science, 5 months ago

3. Answer the following questions in 30-40 words: a) Explain how the absorption of water and minerals would be see the de were lesser in number but of greater thickness...

Accountancy, 5 months ago

How many tyres of impression account...

Chemistry, 10 months ago

Balance equation for carbon + oxygen= carbon dioxide + heat...

English, 10 months ago

List any ten possible reasons for the decline of sparrow population...

Chemistry, 1 year ago

The vapour pressure of water at 20°C is 17.5 mm Hg. If 18 g of glucose (C₆H₁₂O₆) is added to 178.2 g of water at 20°C, the vapour pressure of the resulting solution will be (a) 17.325 mm Hg (b) 15.750 mm Hg (c) 16.500 mm Hg (d) 17.500 mm Hg...

Chemistry, 1 year ago

Two liquids X and Y form an ideal solution. At 300 K, vapour pressure of the solution containing 1 mol of X and 3 mol of Y is 550 mm Hg. At the same temperature, if 1 mol of Y is further added to this solution, vapour pressure of the solution increases by 10 mm Hg. Vapour pressure ( in mm Hg) of X and Y in their pure states will be, respectively: (a) 300 and 400 (b) 400 and 600 (c) 500 and...

Chemistry, 1 year ago

A 5.25% solution of a substance is isotonic with a 1.5% solution of urea (molar mass = 60 g mol⁻¹) in the same solvent. If the densities of both the solutions are assumed to be equal to 1.0 g cm⁻³, molar mass of the substance will be (a) 210.0 g mol⁻¹ (b) 90.0 g mol⁻¹ (c) 115.0 g mol⁻¹ (d) 105.0 g mol⁻¹.