The defective eye of a person has near point 0.5 m and point 3 m. The power far corrective lens required for
(i) reading purpose and
(ii) seeing distant objects, respectively are:
(a) 0.5 D and +3D
(b) +2D and – \frac{1}{3} D
(c) – 2D and + \frac{1}{3}D
(d) 0.5 D and-3.0 D
Answers
Answered by
2
Answer:
I think option a) 0.5D and +3D
Answered by
3
Answer:
Option A - 0.5 D and +3D
Hope it helps you......✔✔✔
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