Question

the defferent between two numbers is 7. six times the smaller plus the largest is 77. find the number ? stap by step solve
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Answer 1

Required Answer :

1st number = 17

2nd number = 10

Given :

Difference between two numbers = 7

six times smaller number + bigger number = 77

To find :

we have to find numbers.

Explanation :

let the one number = x

so, by the given question,

if one number is x then other = x - 7

so,

The two numbers are :

x and x - 7

So, here we have smaller number is x - 7 nd,

bigger number = x

Now, Solving it -

Given,

six times smaller number + bigger number = 77

=> 6 ( x - 7 ) + x = 77

=> 6x - 42 + x = 77

=> 7x - 42 = 77

=> 7x = 77 + 42

=> 7x = 119

$x \: = \: \frac{119}{7} \\ = > 17$

Here ,

We found that the value of x = 17

so,

We know that another number = x - 7

=> 17 - 7

=> 10.

Hence,

According to the Given Explanation, We find out that two numbers are :-

17 and 10

Answer 2

*Answer:

Required Answer :

1st number = 17

2nd number = 10

Given :

Difference between two numbers = 7

six times smaller number + bigger number = 77

To find :

we have to find numbers.

Explanation :

let the one number = x

so, by the given question,

if one number is x then other = x - 7

so,

The two numbers are :

x and x - 7

So, here we have smaller number is x - 7 nd,

bigger number = x

Now, Solving it -

Given,

six times smaller number + bigger number = 77

=> 6 ( x - 7 ) + x = 77

=> 6x - 42 + x = 77

=> 7x - 42 = 77

=> 7x = 77 + 42

=> 7x = 119

$= > \: x = \frac{119}{7} \\ = > x = 17$