The degeneracy of an excited state of nitrogen atom having electronic configuration 1s22s22p23d1
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The question is incomplete and vague as the electronic configuration of the Nitrogen atom is not given. However, I am giving an assumed answer considering the question to be the popular academic question.
The electronic configuration of the Nitrogen atom is given as - 1s²2s²2p²3d¹. The degeneracy of the nitrogen atom in its excited state in the given electronic configuration is - 150.
The degeneracy is calculated as the n² for the nth level of energy. It is given by 2l + 1 for the same energy levels. So, the last orbital in the given configuration is 3d¹, which means that the orbitals that have already been filled are - 1s - 2s - 2p -. 3s - 3p - 3d.
So, the degeneracy can be calculated to give a value of - 150.
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The electronic configuration of the Nitrogen atom is given as - 1s²2s²2p²3d¹. The degeneracy of the nitrogen atom in its excited state in the given electronic configuration is - 150.
The degeneracy is calculated as the n² for the nth level of energy. It is given by 2l + 1 for the same energy levels. So, the last orbital in the given configuration is 3d¹, which means that the orbitals that have already been filled are - 1s - 2s - 2p -. 3s - 3p - 3d.
So, the degeneracy can be calculated to give a value of - 150.
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The electron configuration of an excited state of nitrogen atom is 1s2 2s2 2p2 3d1. the degeneracy of the state is
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